3x-[x+(4x+1)+3]=6

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Solution for 3x-[x+(4x+1)+3]=6 equation:


Simplifying
3x + -1[x + (4x + 1) + 3] = 6

Reorder the terms:
3x + -1[x + (1 + 4x) + 3] = 6

Remove parenthesis around (1 + 4x)
3x + -1[x + 1 + 4x + 3] = 6

Reorder the terms:
3x + -1[1 + 3 + x + 4x] = 6

Combine like terms: 1 + 3 = 4
3x + -1[4 + x + 4x] = 6

Combine like terms: x + 4x = 5x
3x + -1[4 + 5x] = 6
3x + [4 * -1 + 5x * -1] = 6
3x + [-4 + -5x] = 6

Reorder the terms:
-4 + 3x + -5x = 6

Combine like terms: 3x + -5x = -2x
-4 + -2x = 6

Solving
-4 + -2x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2x = 6 + 4

Combine like terms: -4 + 4 = 0
0 + -2x = 6 + 4
-2x = 6 + 4

Combine like terms: 6 + 4 = 10
-2x = 10

Divide each side by '-2'.
x = -5

Simplifying
x = -5

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